0=2x(2.718^(2x))+(2.718^(2x))

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Solution for 0=2x(2.718^(2x))+(2.718^(2x)) equation: 



0=2x(2.718^(2x))+(2.718^(2x))

We move all terms to the left:

0-(2x(2.718^(2x))+(2.718^(2x)))=0

We add all the numbers together, and all the variables

-(2x(2.718^2x)+(2.718^2x))=0



We calculate terms in parentheses: -(2x(2.718^2x)+(2.718^2x)), so:

2x(2.718^2x)+(2.718^2x)

We multiply parentheses

4x^2+(2.718^2x)

We get rid of parentheses

4x^2+2.718^2x

Back to the equation:

-(4x^2+2.718^2x)



We get rid of parentheses

-4x^2-2.718^2x=0

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